Suppose the population standard deviation, σ, is 30 based upon previous studies. We would like to estimate the population mean within ±10 of its true value, at a significance level of .05 (95% Confidence interval). What sample size should be taken?
Solution :
Given that,
standard deviation = = 30
margin of error = E = 10
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Sample size = n = ((Z/2 * ) / E)2
= ((1.960 * 30) / 10)2
= 34.57
= 35
Sample size = 35
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