In a mid-size company, the distribution of the number of phone
calls answered each day by each of the 12 receptionists is
bell-shaped and has a mean of 64 and a standard deviation of 11.
Using the empirical rule (as presented in the book), what is the
approximate percentage of daily phone calls numbering between 53
and 75?
Do not enter the percent symbol.
ans = %
Solution :
Given that ,
mean = = 64
standard deviation = = 11
P(53 < x < 75) = P[(53 - 64)/ 11) < (x - ) / < (75 - 64) / 11) ]
= P(-1.00 < z < 1.00)
= P(z < 1.00) - P(z < -1.00)
Using z table,
= 0.84 - 0.16
= 0.68
Using Empirical rule,
P( - < x < + ) = 68
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