The mean lifetime of a tire is 46 months with a variance of 49.
If 133 tires are sampled, what is the probability that the mean of the sample would differ from the population mean by less than 1.05 months? Round your answer to four decimal places.
Solution :
Given that,
mean = = 46
standard deviation = = 7
= / n = 7 / 133 = 0.6070
= P[(-1.05) /0.6070 < ( - ) / < (1.05) / 0.6071)]
= P(-1.73 < Z < 1.73)
= P(Z < 1.73) - P(Z < -1.73)
= 0.9582 - 0.0418
= 0.9164
Probability = 0.9164
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