We want to compare the serum cholesterol levels of recent immigrants with the levels found in the general population of the US. It is known that the mean cholesterol level for a certain age group in the US is 189 mg/dL. A random sample of 100 recent immigrants of the same age group finds a mean of 180 mg/dL. Assume that a population standard deviation is 49. Test at the 5% level to see if the level for recent immigrants is different. Give the null and alternate hypotheses. Decide if you accept or reject the null hypothesis
Solution :
This is the two tailed test,
The null and alternative hypothesis is ,
H0 : = 189
Ha : 189
Test statistic = z =
= ( - ) / / n
= (180 - 189) / 49 / 100
Test statistic = z = -1.84
P(Z < -1.84) = 0.0329
P-value = 2 * P(Z < -1.84)
P-value = 2 * 0.0329
P-value = 0.0658
= 0.05
P-value >
Fail to reject the null hypothesis .
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