Question

5) Here are some (simulated) data on the maximum age distribution in rabbits: age: 0 1 2 3 4 5 6 7 8 9 frequency: 47 232 429 388 205 99 58 10 3 0 Give the following:

a) Pr(Y > 6)

b) Pr(2 < Y < 6)

c) Pr(Y ≥ 3)

d) Pr(Y < 7)

e) Pr(Y = 9)

e) Add (a) and (d). Are you surprised? Why or why not?

Answer 1

(a)

So,

Answer is:

0.009148

(b)

(a)

So,

Answer is:

0.470428

(c)

So,

Answer is:

0.518695

(d)

So,

Answer is:

0.991162

(e)

Pr(Y= 9) = 0/1471 = 0

So,

Answer is:

0

(e)

Add (a) and (d): We get:

0.009148+ 0.991162 = 1.0003105

We are not surprised.

Reason: (a) is P(Y>6).   (b) is P(Y<7). So, when we add (a) and (b), P(Y=7) is added to 1.000. That is the reason for slight increase from 1.00 seen in the addition.