Question

An engineer wants to determine how the weight of a gas-powered car, x, affects gas mileage, y. The accompanying data represent the weights of various domestic cars and their miles per gallon in the city for the most recent model year. Complete parts (a) through (d) below. LOADING... Click here to view the weight and gas mileage data. (a) Find the least-squares regression line treating weight as the explanatory variable and miles per gallon as the response variable. ModifyingAbove y with caret y equals = nothing x plus + nothing (Round the x coefficient to five decimal places as needed. Round the constant to two decimal places as needed.    weight(pounds),x 3765 3847 2677 3622 3265 2877 3628 2609 3556 3701 3229 miles per gallon,y 16 15 24 19 20 24 16 24 18 16 17.Thank you P'm so frustrated with this math.

Answer 1

Sum of X = 36776
Sum of Y = 209
Mean X = 3343.2727
Mean Y = 19
Sum of squares (SS_X) = 1983246.1818
Sum of products (SP) = -14604

Regression Equation = ŷ = bX + a

b = SP/SS_X = -14604/1983246.18 = -0.00736

a = M_Y - bM_X = 19 - (-0.01*3343.27) = 43.62

ŷ = -0.00736X + 43.62