Number of Prior Police Contacts (X) |
Number of Offenses (Y) |
3 |
3 |
4 |
6 |
7 |
5 |
1 |
0 |
0 |
1 |
0 |
2 |
5 |
6 |
3 |
4 |
Step 1: State the H0 and the H1.
Step 2: Identify the distribution and compute the df.
The distribution is the t distribution.
df =
Step 3: Identify the critical value of the test statistic and state the decision rule.
α = .05
two-tailed test of significance
critical value =
Step 4: Compute the obtained value of the test statistic
Number of Prior Police Contacts (x) |
Number of Offenses (y) |
xy |
x2 |
y2 |
3 |
3 |
|||
4 |
6 |
|||
7 |
5 |
|||
1 |
0 |
|||
0 |
1 |
|||
0 |
2 |
|||
5 |
6 |
|||
3 |
4 |
|||
Sx = |
Sy = |
Sxy = |
Sx2 = |
Sy2= |
Step 5: Make a decision about the null and state the substantive conclusion.
Decision Rule:
Reject null if:
tobt is less than tcrit.
OR
tobt is greater than tcrit
Use sign, magnitude and Coefficient of Determination (r2)
Sign
Magnitude
A very general guideline is that values between 0 and
Coefficient of Determination
Get Answers For Free
Most questions answered within 1 hours.