16. The following resting data were collected from three different sports teams (hockey, rugby and football). Ignoring the sport played, run a Kolmogorov–Smirnov test on the age variable. What is the correct expression for the result?
ID |
Sport |
Age (y) |
Body mass (kg) |
Stature (m) |
Resting heart rate (bpm) |
Resting systolic blood pressure (mmHg) |
Resting diastolic blood pressure (mmHg) |
Resting mean arterial pressure (mmHg) |
1 |
Hockey |
18 |
79 |
1.83 |
65 |
121 |
79 |
93 |
2 |
Hockey |
20 |
79.9 |
1.78 |
50 |
127 |
81 |
96 |
3 |
Hockey |
25 |
75.8 |
1.83 |
53 |
120 |
62 |
81 |
4 |
Hockey |
17 |
63.6 |
1.7 |
74 |
115 |
75 |
88 |
5 |
Hockey |
22 |
57.4 |
1.64 |
68 |
116 |
68 |
84 |
6 |
Hockey |
22 |
60 |
1.65 |
64 |
100 |
30 |
53 |
7 |
Hockey |
21 |
81.2 |
1.79 |
65 |
126 |
80 |
95 |
8 |
Hockey |
19 |
84.5 |
1.93 |
64 |
120 |
70 |
87 |
9 |
Rugby |
19 |
71.1 |
1.77 |
79 |
120 |
80 |
93 |
10 |
Rugby |
26 |
72.8 |
1.79 |
82 |
134 |
76 |
95 |
11 |
Rugby |
29 |
75.1 |
1.78 |
55 |
130 |
90 |
103 |
12 |
Rugby |
21 |
69.4 |
1.74 |
60 |
140 |
71 |
94 |
13 |
Rugby |
19 |
68.8 |
1.8 |
76 |
122 |
78 |
93 |
14 |
Rugby |
19 |
63.8 |
1.6 |
61 |
119 |
74 |
89 |
15 |
Rugby |
19 |
87 |
1.87 |
60 |
130 |
80 |
97 |
16 |
Football |
24 |
74.2 |
1.77 |
63 |
120 |
64 |
83 |
17 |
Football |
26 |
80.9 |
1.82 |
65 |
110 |
79 |
89 |
18 |
Football |
27 |
66.5 |
1.75 |
63 |
120 |
50 |
73 |
19 |
Football |
19 |
83 |
1.81 |
49 |
120 |
80 |
93 |
20 |
Football |
21 |
89.5 |
1.78 |
50 |
117 |
80 |
92 |
21 |
Football |
19 |
74.2 |
1.77 |
72 |
114 |
78 |
90 |
22 |
Football |
21 |
66.6 |
175 |
83 |
122 |
82 |
95 |
a. |
D(22) = .197, p = .026 |
|
b. |
D(22) = .026, p = .197 |
|
c. |
D(22) = .086, p > .2 |
|
d. |
D(22) = .2, p > .086 |
17. Why does a Shapiro–Wilk test sometimes conclude that the data are not normally distributed (i.e. significant) when a Kolmogorov–Smirnov test is non-significant?
a. |
The Shapiro–Wilk test is more powerful. |
|
b. |
The Shapiro–Wilk test is less powerful. |
|
c. |
The Shapiro–Wilk test does not work well when there are a large number of cases. |
|
d. |
The Shapiro–Wilk test is a more conservative test. |
18. Using the data from the table in Q16, what assumption can be made regarding the distribution of the age data?
a. |
They are not normally distributed. |
|
b. |
They are normally distributed. |
|
c. |
It is unclear whether they are normally distributed or not. |
|
d. |
A Shapiro–Wilk test should be run to confirm the result. |
20.
Using the data in the table in Q16, split the data according to the sport. Run a Kolmogorov–Smirnov test on the diastolic blood pressure data. Which group’s data cannot assume a normal distribution?
a. |
Football |
|
b. |
Hockey |
|
c. |
Rugby |
|
d. |
All three are normally distributed. |
Shapiro-Wilk test, using right-tailed normal distribution
1. H0
hypothesis
Since p-value<α, H0 is rejected.
It is assumed that the data is not normally distributed.
In other words, the difference between the data sample and the
normal distribution is big enough to be statistically
significant.
2.
P-value
p-value is 0.0213364, hence, the chance of type1
error (rejecting a correct H0) is small:
0.02134(2.13%)
The smaller the p-value, the more it supports H1
3. The
statistics
W is 0.892743. It is not in the 95% critical value
accepted range: [0.9112: 1.0000]
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