The population standard deviation for the height of college football players is 3.3 inches. If we want to estimate a 90% confidence interval for the population mean height of these players with a 0.7 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:
Solution :
Given that,
standard deviation = = =3.3
Margin of error = E = 0.7
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645 ( Using z table ( see the 0.05 value in standard
normal (z) table corresponding z value is 1.645 )
sample size = n = [Z/2* / E] 2
n = ( 1.645 * 3.3 / 0.7 )2
n =60.14
Sample size = n =61 approximately
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