a urn contains 7 red marbles and 3 white marbles. three marbles are drawn from the urn one after the other. Find the probability that the first two are red and the third is white
Answer : 7/40 or 0.175
There are 7 red and 3 white marbles. Hence there are a total of 10 marbles. The probability that the first marble picked is red is 7/10. Now we are left with 6 red marbles and a total of 9 marbles. Hence the probability that the second marble picked is red is 6/9. Now we are left with 3 white marbles and a total of 8 marbles. Hence the probability that the third marble picked is white is 3/8. Hence the required probability is as follows
Hence the required probability is 0.175
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