Question

Let a population consist of the values 10 cigarettes, 19 cigarettes, and 20 cigarettes smoked in a day. Show that when samples of size 2 are randomly selected with replacement, the samples have mean absolute deviations that do not center about the value of the mean absolute deviation of the population. What does this indicate about a sample mean absolute deviation being used as an estimator of the mean absolute deviation of a population?

Answer #1

The mean is the sum of all values divided by the number of values :

n is the number of values in the dataset:n = 3

The population mean absolute deviation is the sum of all absolute deviations of the mean, divided by the number of data values n

Here are all possible samples having two values from the list 19,10,20

The means of all sample mean absolute deviations is 2.2222 which is not the same as the population MAD of 6.67 and thus the sample mean absolute deviation is not an unbiased estimator of the population mean absolute deviation

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d below.
4,4 4,5 4,9 5,4
5,5 5,9
9,4 9,5
9,9
A.) Find the value of the population standard deviation
B.) Find the standard deviation of each of the nine samples,
then summarize the sampling distribution of the standard deviations
in the format of a table...

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2,2 2,4 2,12 4,2 4,4 4,12 12,2 12,4 12,12
a. Find the value of the population standard deviation
sigma.
sigma =
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P(X < 188.1) =
Find the probability that a sample of size n=193 is randomly
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The assets (in billions of dollars) of the four wealthiest
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after
35
17
12
29
18
19
27
26
16
41
46
17
21
34
31
20
34
26
27
41
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before
after
46
17
21
34
31
20
34
26
27
41
35
17
12
29
29
19
27
26
16
41
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