Question

Candy Bowl"

You have a bowl of candy that contains 10 Snickers, 10 Milky Ways, 10 Twix, and 10 M&M packs.

1. If in #4 you get a Milky Way, KEEP it, and select again, what is the probability your second choice will be M&Ms?

2. What is the probability that in making two selections (keeping out the first one), that you will choose two Snickers? NOTE: Now I’m asking about the probability of both!

3. What is the probability that in making two selections (keeping out the first one), that you will get a Twix first and then a Snickers?

Answer #1

Q1) Given that one Milky Way is taken out, the probability that
the second choice will be a M&M is computed here as:

= Number of M&Ms in the bowl of candy / Total candies left

= 10 / 39

= 0.2564

**Therefore 0.2564 is the required probability
here.**

Q2) The probability of getting two snickers is computed here
as:

= Number of ways to select 2 snickers from 10 snickers / Total ways
to select 2 chocolates from 40 chocolates

**Therefore 0.0577 is the required probability
here.**

Q3) The probability that we get a Twix first and then a snickers
is computed here as:

= Probability of getting a Twin first * Probability of getting a
snicker given that a Twix was taken out

= (10/40)*(10/39)

= 0.0641

**Therefore 0.0641 is the required probability
here.**

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