Question

- The results of a sample of 372 subscribers
to
*Wired*magazine shows the time spent using the Internet during the week. Previous surveys have revealed that the population standard deviation is 10.95 hours. The sample data can be found in the Excel test data file.- What is the probability that another sample of 372 subscribers spends less than 19.00 hours per week using the Internet?
- Develop a 95% confidence interval for the population mean
- If the editors of
*Wired*wanted to have the error be no more than 1 hour, using the same 95% confidence interval, what size of sample would be required.

Excel Data

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Answer #1

∑x = 7347

n = 372

Mean , x̅ = Ʃx/n = 7347/372 = 19.75

µ = 19.75, σ = 10.95, n = 372

P(X̅ < 19) =

= P( (X̅-μ)/(σ/√n) < (19-19.75)/(10.95/√372) )

= P(z < -1.321)

Using excel function:

= NORM.S.DIST(-1.321, 1)

= **0.0932**

----

Population standard deviation, σ = 10.95

Margin of error, E = 1

Confidence interval, CL = 0.95

Significance level, α = 1-CL = 0.05

Critical value, z = NORM.S.INV(0.05/2) = 1.9600

Sample size, n = (z * σ / E)² = (1.96 * 10.95 / 1)² = 460.6 =
**461**

____________________________________________
The results of a sample of 372 subscribers to Wired
magazine shows the time spent using the Internet during the week.
Previous surveys have revealed that the population standard
deviation is 10.95 hours. The sample data can be found in the Excel
test data file.
What is the probability that another sample of 372 subscribers
spends less than 19.00 hours per week using the Internet?
____________________________________________
Develop a 95% confidence interval for the population mean
____________________________________________
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