Question

Listed below are systolic blood pressure measurements​ (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be​ concluded?

Identify hypothesis.

Identify the test statistic.

t=

​(Round to two decimal places as​ needed.)

Identify the​ P-value.

​P-value=

​(Round to three decimal places as​ needed.)

What is the conclusion based on the hypothesis​ test?

Since the​ P-value is less/greaterthan the significance​ level,reject/fail to reject the null hypothesis. There is/is not sufficient evidence to support the claim of a difference in measurements between the two arms.

Right_arm(mm_Hg)   Left_arm(mm_Hg)
142   181
143   165
131   185
133   140
129   153

Answer 1

t = -3.65

P-value = 0.022

Since the​ P-value is less than the significance​ level,reject the null hypothesis. There is sufficient evidence to support the claim of a difference in measurements between the two arms.