[3] In our class meeting 44% of the people had blue pants on, 23% had black pants on, 21% had white pants on and the rest had green. If I were to pick a person at random from this meeting, what is the probability that they would have green or black pants on?
Let , A be the event that the people had a blue pant.
Let , B be the event that the people had a black pant.
Let , C be the event that the people had a white pant.
Let , D be the event that the people had a green pant.
Given : P(A)=0.44 , P(B)=0.23 , P(C)=0.21 , P(D)=1-0.44-0.23-0.21=0.12
Now , assume that the all events are independent.
By using addition rule ,
; Since , D and B are independent.
Therefore , the probability that they would have green or black pants on is 0.3224
Get Answers For Free
Most questions answered within 1 hours.