Question

Question 30

You are going to sample from a population that is normally distributed with μ=90 and a σ=12, if you sample four scores from the population what is the probability that the sample mean will be at least six above the population mean, in other words, p( M ≥ 96)=?

Answer 1

Solution :

Given that ,

= 90

= / n = 12 / 4 = 6

P(M 96) = 1 - P(M 96)

= 1 - P[(M - ) / (96 - 90) / 6]

= 1 - P(z 1.00)   

= 1 - 0.8413

= 0.1587