Question

A random sample of Miami University students finds that 100 of the 500 sampled participate in...

A random sample of Miami University students finds that 100 of the 500 sampled participate in intramural sports. Find a 95% confidence interval for the true proportion of all students that participate in intramural sports.

Group of answer choices

[0.171, 0.229]

[0.190, 0.210]

[99.965, 100.035]

[0.165, 0.235]

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Here, 100 of the 500 sampled participate in intramural sports.

Therefore, the sample proportion , = 100/500

= 0.2

z-value for 95% confidence interval = 1.96

The 95% confidence interval is = z*[(1-)/n]

= 0.2 0.035

= (0.165 , 0.235)

Answer : [0.165, 0.235]

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Problem No. 1.3 Given A sample of 400 engineering students is selected from all students registered...
Problem No. 1.3 Given A sample of 400 engineering students is selected from all students registered at the college of Engineering, and it turns out that 76 of them participate in intramural sports. True or false? Explicit justification of each answer is required. 1. The proportion of students at this college who participate in intramural sports is 19/100 2. The proportion of students at this college who participate in intramural sports is likely to be close to 19/100, but not...
According to a survey of 100 students in a certain university, 25 students are fans of...
According to a survey of 100 students in a certain university, 25 students are fans of Ravens. (a) Calculate a 95% confidence interval for the proportion of students that are fans of Ravens. (b) Interpret the interval you just found in part (a). (c) Assuming no any available information, how large a sample size is necessary if we want a 95% confidence interval with a width of 10%?
In a simple random sample of 500 freshman students, 276 of them live on campus. You...
In a simple random sample of 500 freshman students, 276 of them live on campus. You want to claim that majority of college freshman students in US live on campus. A) Are the assumptions for making a 95% confidence interval for the true proportion of all college freshman students in the United States who live on campus satisfied? yes/no? B) What is the sample proportion? C.) A 95% confidence interval for the actual proportion of college freshman students in the...
Suppose that the heights of 100 male students at BIUST represent a random sample of the...
Suppose that the heights of 100 male students at BIUST represent a random sample of the heights of all 1546 male students at the university. Determine unbiased and efficient estimates of (a) the true mean, (b) the true variance. (C) Find (a) 95%, and  99% confidence intervals for estimating the mean height of the BIUST University students
A random sample of 20 students at a university showed an average age of 20.9 years...
A random sample of 20 students at a university showed an average age of 20.9 years and a sample standard deviation of 2.5 years. The 98% confidence interval for the true average age of all students in the university is? Enter in the upper limit of your confidence interval.
A random sample of 200 students was drawn from a large university. It was found that...
A random sample of 200 students was drawn from a large university. It was found that 73 students in this sample live in off-campus apartment. Construct a 90% confidence interval for the proportion of students in this university that live in off-campus apartment. Use normal approximation in this question. You can also take a look at Wilson score interval.
A random sample of 20 students at a university showed an average age of 21.5 years...
A random sample of 20 students at a university showed an average age of 21.5 years and a sample standard deviation of 2.8 years. The 98% confidence interval for the true average age of all students in the university is? Enter in the upper limit of your confidence interval. ( round to 4 decimal places)
4. A random sample of 450 Bilkent students were asked to rate their university (from 1...
4. A random sample of 450 Bilkent students were asked to rate their university (from 1 to 10) according to their perceptions regarding academic facilities of the university. In the random sample, 200 Indicated a rank value more than 6. For those students: Estimate the value of the population proportion. (Round your answers to 3 decimal places.) POPULATION PROPROTION : …....................? Develop a 98% confidence interval for the population proportion. (Round your answers to 3 decimal places.) CONFIDENCE INTERVAL …..................
Construct a 95% confidence interval by hand for what proportion of students at XYZ University are...
Construct a 95% confidence interval by hand for what proportion of students at XYZ University are vegan, if you took a random sample of 100 students and 3 were vegan. Also comment on if anything concerns you about your interval and what could be causing your concern.   
A survey of 200 students is selected randomly on a large university campus They are asked...
A survey of 200 students is selected randomly on a large university campus They are asked if they use a laptop in class to take notes. The result of the survey is that 70 of the 200 students use laptops to take notes in class. What is the value of the sample proportion? What is the standard error of the sampling proportion? Construct an approximate 95% confidence interval for the true proportion by going 2 standard errors from the sampling...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT