Question
Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly select 8 employees and ask them if they judge co-workers based on this criterion. The random variable is the number of employees who judge their co-workers by cleanliness. Which outcomes of this binomial distribution would be considered unusual?
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3VD. Finding unusual outcomes from a probability distribution (Links to an external site.) (2:32)
Group of answer choices
0, 1, 2, 8
0, 1, 7, 8
1, 2, 8
1, 2, 7, 8
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Question
Eighty-one percent of products come off the line within product specifications. Your quality control department selects 15 products randomly from the line each hour. Looking at the binomial distribution, if fewer than how many are within specifications would require that the production line be shut down (unusual) and repaired?
Homework Help:
3VD. Finding unusual outcomes from a probability distribution (Links to an external site.) (2:32)
Group of answer choices
Fewer than 10
Fewer than 12
Fewer than 11
Fewer than 9
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Question
The probability of a potential employee passing a drug test is 86%. If you selected 12 potential employees and gave them a drug test, how many would you expect to pass the test?
Homework Help:
3DC. Mean, expected value, variance, and standard deviation of discrete variables (Links to an external site.) (DOCX)
Group of answer choices
8 employees
10 employees
9 employees
11 employees
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Question
The probability of a potential employee passing a training course is 86%. If you selected 15 potential employees and gave them the training course, what is the probability that 11 or less will pass the test?
Homework Help:
3VB. Calculating binomial probabilities and cumulative probabilities (Links to an external site.) (8:23)
Group of answer choices
0.100
0.852
0.148
0.862
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Question
Off the production line, there is a 3.7% chance that a candle is defective. If the company selected 45 candles off the line, what is the probability that fewer than 3 would be defective?
Homework Help:
3VB. Calculating binomial probabilities and cumulative probabilities (Links to an external site.) (8:23)
Group of answer choices
0.037
0.768
0.975
0.916
1)
X | P(X) |
0 | 0.0024 |
1 | 0.0215 |
2 | 0.0848 |
3 | 0.1912 |
4 | 0.2695 |
5 | 0.2431 |
6 | 0.1371 |
7 | 0.0442 |
8 | 0.0062 |
unusual outcomes from a probability distribution: 0, 1, 7, 8
========================
Sample size , n = 15
Probability of an event of interest, p = 0.81
unusual outcomes from a probability distribution = Fewer than 10
==================
expected number= Mean = np = 12*0.86= 10.3 ≈ 10 employees
============
P(X ≤ 11 ) = BINOM.DIST(11,15,0.86,TRUE)= 0.148
===============
P(X ≤ 3 ) = BINOM.DIST(3,45,0.037,TRUE)= 0.916
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