Based on historical data, your manager believes that 28% of the
company's orders come from first-time customers. A random sample of
175 orders will be used to estimate the proportion of
first-time-customers. What is the probability that the sample
proportion is greater than than 0.22?
Answer = (Enter your answer as a number accurate to 4
decimal places.)
solution:
Given data
population Proportion (P) = 28% = 0.28
Sample size(n) = 175
Consider the sampling distribution of sample proportion follows normal distribution
So,Here Mean (p) = P = 0.28
Standard deviation (p) =
=
= 0.0339
Probability that sample proportion is greater than 0.22 = P( > 0.22)
=
=
= P(Z>-1.77)
= P(Z<1.77) [since , P(Z>-k) = P(Z<k) ]
= 0.9616 [ using standard normal distribution table ]
Probability that sample proportion is greater than 0.22 = 0.9616
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