Question

We measured the compressive strength for n = 16 specimens of concrete. Using the mean and...

We measured the compressive strength for n = 16 specimens of concrete. Using the mean and standard deviation and assuming a normal population, we computed the following confidence interval [2271.7688, 2308.2312]. This interval is a confidence interval for the mean compressive strength at a level of confidence of 90%. We are told the the sample mean is x = 2290. What is the value of the sample standard deviation s?

Homework Answers

Answer #1

ANSWER::

1)margin of error E=(2308.2312-2271.7688)/2

=18.2312

here for n-1=15 df and 90% CI , crtiical t =1.753

therefore sample standard deviation =E*sqrt(n)/t =18.2312*sqrt(16)/1.753

=41.6

(OR) TRY THIS

NOTE:: I HOPE YOUR HAPPY WITH MY ANSWER....***PLEASE SUPPORT ME WITH YOUR RATING...

***PLEASE GIVE ME "LIKE"...ITS VERY IMPORTANT FOR ME NOW....PLEASE SUPPORT ME ....THANK YOU

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A sample of concrete specimens of a certain type is selected, and the compressive strength of...
A sample of concrete specimens of a certain type is selected, and the compressive strength of each specimen is determined. The mean and standard deviation are calculated as x = 4000 and s = 300, and the sample histogram is found to be well approximated by a normal curve. (a)Approximately what percentage of the sample observations are between 3700 and 4300? (Round the answer to the nearest whole number.) Approximately  % (b) Approximately what percentage of sample observations are outside the...
Testing of a given concrete sample has yielded a normal distribution with a mean compressive strength...
Testing of a given concrete sample has yielded a normal distribution with a mean compressive strength of 3200 psi with a standard deviation of 275 psi. You require a compressive strength of at least 2950 psi.  What is the probability that this concrete meets your needs?
The compressive strength of concrete is normally distributed. A random sample of 11 concrete specimens from...
The compressive strength of concrete is normally distributed. A random sample of 11 concrete specimens from Factory 1 yields a sample mean equal to 1,221.3 pounds per square inch (psi) and a sample variance of 882.0 psi2. A random sample of 11 concrete specimens from Factory 2 yields a sample mean equal to 1,441.2 psi and a sample variance of 856.1 psi2.   If you do a test of hypothesis to see if the means of the concretes from Factory 1...
The compressive strength of concrete is normally distributed with μ = 2500 psi and σ =...
The compressive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. A random sample of n = 5 specimens is taken. What is the standard error of the sample mean? A) 2500 B) 10 C) 22.36 D) 50
The accompanying data is on cube compressive strength (MPa) of concrete specimens. 112.5      97.0     ...
The accompanying data is on cube compressive strength (MPa) of concrete specimens. 112.5      97.0      92.6      86.0      102.0 99.1      95.8      103.5      89.0      86.6 (a) Is it plausible that the compressive strength for this type of concrete is normally distributed? The normal probability plot is not acceptably linear, suggesting that a normal population distribution is plausible. The normal probability plot is acceptably linear, suggesting that a normal population distribution is plausible.     The normal probability...
A new concrete mix is being designed to provide adequate compressive strength for concrete blocks. The...
A new concrete mix is being designed to provide adequate compressive strength for concrete blocks. The specification for a particular application calls for the blocks to have a mean compressive strength µ greater than 1350 kPa. A sample of 100 blocks is produced and tested. Their mean compressive strength is 1356 kPa and their standard deviation is 70 kPa. What is the most appropriate null hypothesis regarding the population mean µ. Indicate the alternate hypothesis as well. Find the P-value....
Strength of concrete: The compressive strength, in kilopascals, was measured for concrete blocks from five different...
Strength of concrete: The compressive strength, in kilopascals, was measured for concrete blocks from five different batches of concrete, both three and six days after pouring. The data are as follows. Can you conclude that the mean strength after three days is greater than the mean strength after six days? Let μ1 represent the mean strength after three days and =μd−μ1μ2. Use the =α0.01 level and the P-value method with the TI-84 Plus calculator. Block 1. 2 3. 4. 5...
Suppose that the compressive strength of concrete is normally distributed with an unknown mu and a...
Suppose that the compressive strength of concrete is normally distributed with an unknown mu and a known sigma of 40 (pounds per square inch). A random sample of size 19 has sample mean 1376. Construct a 92% confidence interval (as crazy and unlikely as it seems to create a 92% CI) for the population mean. Give answer to one decimal place.
For this term, we will create confidence intervals to estimate a population value using the general...
For this term, we will create confidence intervals to estimate a population value using the general formula: sample estimator +/- (reliability factor)(standard error of the estimator) Recall that the (reliability factor) x (standard error of the estimator)= margin of error (ME) for the interval. The ME is a measure of the uncertainty in our estimate of the population parameter. A confidence interval has a width=2ME. A 95% confidence interval for the unobserved population mean(µ), has a confidence level = 1-α...
If X = 79​, S = 17​, and n = 16​, and assuming that the population...
If X = 79​, S = 17​, and n = 16​, and assuming that the population is normally​ distributed, construct a 90 % confidence interval estimate of the population​ mean, u.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT