We measured the compressive strength for n = 16 specimens of concrete. Using the mean and standard deviation and assuming a normal population, we computed the following confidence interval [2271.7688, 2308.2312]. This interval is a confidence interval for the mean compressive strength at a level of confidence of 90%. We are told the the sample mean is x = 2290. What is the value of the sample standard deviation s?
ANSWER::
1)margin of error E=(2308.2312-2271.7688)/2
=18.2312
here for n-1=15 df and 90% CI , crtiical t =1.753
therefore sample standard deviation =E*sqrt(n)/t =18.2312*sqrt(16)/1.753
=41.6
(OR) TRY THIS
NOTE:: I HOPE YOUR HAPPY WITH MY ANSWER....***PLEASE SUPPORT ME WITH YOUR RATING...
***PLEASE GIVE ME "LIKE"...ITS VERY IMPORTANT FOR ME NOW....PLEASE SUPPORT ME ....THANK YOU
Get Answers For Free
Most questions answered within 1 hours.