determine the 99% confidence interval estimate for the population of a noaml distributed given
n= 81 s(d)= 104 x= 1,200
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By Hand calculation:
Standard error = s(d) / = 104 / = 11.55556
z value for 99% confidence interval is 2.575829
Margin of error = Standard error * z
= 11.55556 * 2.575829
= 29.76515
99% confidence interval estimate
(Mean - Margin of error, Mean + Margin of error)
(1200 - 29.76515, 1200 + 29.76515)
(1170.235, 1229.765)
Using Excel, the margin of error is found by the below function,
=CONFIDENCE.NORM(0.01,104,81)
1st input is = 1 - Confidence level = 1 - 0.99 = 0.01
2nd input is s(d) (Standard deviation)
3rd input is sample size n.
So, 99% confidence interval estimate is Excel can be forund by below formula,
=1200 - CONFIDENCE.NORM(0.01,104,81)
and
=1200 + CONFIDENCE.NORM(0.01,104,81)
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