The mean number of words per minute (WPM) read by sixth graders is 93 with a standard deviation of 22. If 30 sixth graders are randomly selected, what is the probability that the sample mean would be greater than 97.95 WPM? (Round your answer to 4 decimal places). Show work.
Solution :
Given that ,
mean = = 93
standard deviation = = 22
= / n = 22 / 30 = 4.0166
P( > 97.95) = 1 - P( < 97.95)
= 1 - P[( - ) / < (97.95 - 93) / 4.0166]
= 1 - P(z < 1.23)
= 1 - 0.8907
= 0.1093
Probability = 0.1093
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