The lengths of nails produced in a factory are normally distributed with a mean of 6.13 centimeters and a standard deviation of 0.06 centimeters. Find the two lengths that separate the top 7% and the bottom 7%. These lengths could serve as limits used to identify which nails should be rejected. Round your answer to the nearest hundredth, if necessary.
Solution:-
Given that,
mean = = 6.13
standard deviation = = 0.06
Using standard normal table,
this is right tail
P(Z > z) = 7%
= 1 - P(Z < z) = 0.07
= P(Z < z) = 1 - 0.07
= P(Z < z ) = 0.93
= P(Z <1.48 ) = 0.93
z = 1.48 ( using z table )
Using z-score formula,
x = z * +
x = 1.48* 0.06+6.13
x = 6.2188 centimeters
x=6.22 rounded
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