The following table shows age distribution and location of a random sample of 166 buffalo in a national park.
Age | Lamar District | Nez Perce District | Firehole District | Row Total |
Calf | 9 | 13 | 19 | 41 |
Yearling | 10 | 10 | 13 | 33 |
Adult | 36 | 26 | 30 | 92 |
Column Total | 55 | 49 | 62 | 166 |
Use a chi-square test to determine if age distribution and location are independent at the 0.05 level of significance.
a) Find or estimate the P-value of the sample test
statistic. (Round your answer to three decimal places.)
b) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis of independence?
Since the P-value > ?, we fail to reject the null hypothesis.
Since the P-value > ?, we reject the null hypothesis.
Since the P-value ? ?, we reject the null hypothesis.
Since the P-value ? ?, we fail to reject the null hypothesis.
c) Interpret your conclusion in the context of the application.
At the 5% level of significance, there is sufficient evidence to conclude that age distribution and location are not independent.
At the 5% level of significance, there is insufficient evidence to conclude that age distribution and location are not independent.
here the expected table is given below.
Age | Lamar District | Nez Perce District | Firehole District | Row Total |
Calf | 13.58 | 12.10 | 15.31 | 41 |
Yearling | 10.93 | 9.74 | 12.33 | 33 |
Adult | 30.48 | 27.16 | 34.36 | 92 |
Column Total | 55 | 55 | 55 | 165 |
Here the chi-square table is given below.
where
X2 =
Age | Lamar District | Nez Perce District | Firehole District | Row Total |
Calf | 1.55 | 0.07 | 0.89 | 2.50 |
Yearling | 0.08 | 0.01 | 0.04 | 0.12 |
Adult | 1.00 | 0.05 | 0.55 | 1.60 |
Column Total | 2.63 | 0.12 | 1.48 | 4.23 |
Here
p - value = Pr(X2 > 4.23; dF = 2 * 2 = 4) = 0.3762
(b) Since the P-value > ?, we fail to reject the null hypothesis. Option A is correct.
(c) At the 5% level of significance, there is insufficient evidence to conclude that age distribution and location are not independent.
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