Question

A publisher reports that 46%46% of their readers own a personal computer. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 100 found that 42%42% of the readers owned a personal computer. Determine the P-value of the test statistic. Round your answer to four decimal places.

Answer 1

Solution :

This is the two tailed test .

The null and alternative hypothesis is

H0 : p = 0.46

Ha : p 0.46

n = 100

= 0.42

P0 = 0.46

1 - P0 =1 - 0.46 = 0.54

Test statistic = z

= - P0 / [P0 * (1 - P0 ) / n]

= 0.42 - 0.46/ [0.46 *0.54 / 100]

= −0.803

Test statistic = z = −0.80

2 *P(z < −0.80 ) =2 * 0.2119

P-value = 0.4238