Question

A seat belt manufacturer, who provides seat belts for Volkswagen cars, claims that his product has...

A seat belt manufacturer, who provides seat belts for Volkswagen cars, claims that his product has a mean breaking strength of 250 kg with a standard deviation of 3.5 kg. You select a random sample of 49 of his seat belts and compute the mean breaking strength of your sample to be 245 kg. Test the manufacturer's claim at (letter alpha) α=.05.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Solution :

This is two tailed test .

The null and alternative hypothesis is ,

H0 :   = 250

Ha : 250

Test statistic (t) =

= ( - ) / s / n

= (245 - 250) / 3.5 / 49

Test statistic = -10

P-value = 0

= 0.05

P-value <

Reject the null hypothesis

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A car manufacturer claims that the bumper on its cars is constructed in such a way...
A car manufacturer claims that the bumper on its cars is constructed in such a way that if the car is driven into a wall at a speed of 15 miles per hour the damage to the car would cost about $200 to fix, on average.  A consumer testing agency wants to check the manufacturer's claim that average (or mean) expenditure for bumper repair is equal to $200 against the alternative hypothesis that mean expenditure is not equal to $200 at...
A manufacturer of car batteries claims that his product will last at least 4 years on...
A manufacturer of car batteries claims that his product will last at least 4 years on average. A sample of 50 is taken and the mean and standard deviation are found. The test statistic is calculated to be -1.82. Using a 5% significance level, the conclusion would be: There is sufficient evidence for the manufacturer's claim to be considered correct. There is insufficient evidence for the manufacturer's claim to be considered correct. There is sufficient evidence for the manufacturer's claim...
The manufacturer of a particular cold medicine claims that its’ product provides relief from symptoms in...
The manufacturer of a particular cold medicine claims that its’ product provides relief from symptoms in 30.00 minutes, on average. To test this claim ( i.e., the “null hypothesis” is that the population mean = 30.00), a sample of 144 cold sufferers were offered the medicine ( so, “n” = 144). The ( sample) mean time to relief was 31.14 minutes, with a standard deviation = 9.00 minutes. a.) Can the manufacturer’s claim be rejected, based on this sample (use...
The manufacturer of an over-the-counter pain reliever claims that its product brings pain relief to headache...
The manufacturer of an over-the-counter pain reliever claims that its product brings pain relief to headache suffers in less than 3.5 minutes, on average. In order to be able to make this claim in its television advertisements, the manufacturer was required by a particular television network to present statistical evidence in support of the claim. The manufacturer reported that for a sample of 50 headache sufferers, the mean time to relief was 3.11 minutes and the standard deviation was 69.84...
A manufacturer of auto engine oil claims that cars using their product can go an average...
A manufacturer of auto engine oil claims that cars using their product can go an average of 180 days without changing oil, with a standard deviation of 4 days. The distribution of the length of time between oil changes with this engine oil is known to be left-skewed. To test this claim a gas station owner takes a sample of 100 cars using this brand, and computes the sample mean. Assuming that the manufacturer’s claim is correct, which of the...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used under normal driving conditions. A firm that requires a larger number of these tires wants to test the claim. If the claim is correct, the firm will purchase the manufacturer’s tires; otherwise, the firm will seek another supplier. Now a random sample of 100 tires is taken and the mean and standard deviation of the 100 tires are found. Using these sample results, a...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used under normal driving conditions. A firm that requires a larger number of these tires wants to test the claim. If the claim is correct, the firm will purchase the manufacturer’s tires; otherwise, the firm will seek another supplier. Now a random sample of 100 tires is taken and the mean and standard deviation of the 100 tires are found. Using these sample results, a...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used under normal driving conditions. A firm that requires a larger number of these tires wants to test the claim. If the claim is correct, the firm will purchase the manufacturer’s tires; otherwise, the firm will seek another supplier. Now a random sample of 100 tires is taken and the mean and standard deviation of the 100 tires are found. Using these sample results, a...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used under normal driving conditions. A firm that requires a larger number of these tires wants to test the claim. If the claim is correct, the firm will purchase the manufacturer’s tires; otherwise, the firm will seek another supplier. Now a random sample of 100 tires is taken and the mean and standard deviation of the 100 tires are found. Using these sample results, a...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT