An imaginary study states that Americans watch an average of 1400 hours of streaming videos each year. If the standard deviation of the distribution is 221 hours, find the probability that the mean of a randomly selected sample of 50 Americans will be between 1380 and 1430 hours.
Solution :
= / n = 221 / 50 = 31.2541
= P[(1380 - 1400) / 31.2541 < ( - ) / < (1430 - 1400) / 31.2541)]
= P(-0.64 < Z < 0.96)
= P(Z < 0.96) - P(Z < -0.64)
= 0.8315 - 0.2611
= 0.5704
Probability = 0.5704
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