Coal is carried from a mine in West Virginia to a power plant in New York in hopper cars on a long train. The automatic hopper car loader is set to put 80 tons of coal into each car. The actual weights of coal loaded into each car are normally distributed, with mean μ = 80 tons and standard deviation σ = 1.4 ton.
(a) What is the probability that one car chosen at random will
have less than 79.5 tons of coal? (Round your answer to four
decimal places.)
(b) What is the probability that 44 cars chosen at random will have
a mean load weight x of less than 79.5 tons of coal?
(Round your answer to four decimal places.)
Solution :
(a)
P(x < 79.5) = P[(x - ) / < (79.5 - 80) / 1.4]
= P(z < -0.36)
= 0.3594
Probability = 0.3594
(b)
= / n = 1.4 / 44 = 0.2111
P( < 79.5) = P(( - ) / < (79.5 - 80) / 0.2111)
= P(z < -2.37)
= 0.0089
Probability = 0.0089
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