“Boston Bob’s Best BBQ Blazed Beefy Burgers” claims with 95% confidence, that at least 88% of the customers like the new cheeseburger. A sample of 50 customers shows that 36 of them approve.
H0: __________
H1: __________
P=__________
Is the claim correct? (Reject / Fail to Reject)__________
Solution :
This is the right tailed test .
The null and alternative hypothesis is
H0 : p = 0.88
Ha : p >0.88
n = 50
x = 36
= x / n = 36 / 50 =0.72
P0 = 0.88
1 - P0 = 1 - 0.88 = 0.12
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
= 0.72 - 0.88/ [(0.88*0.12) / 50 ]
= -3.48
Test statistic = z = -3.48
P(z > -3.48 ) = 1 - P(z < -3.48) = 1 - 0.0003
P-value = 0.9997
= 0.05
P-value >
0.9997 > 0.05
Fail to reject the null hypothesis .
There is not sufficient evidence to suggest that
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