Find a confidence interval for μ assuming that each sample is from a normal population. (Round the value of t to 3 decimal places and your final answers to 2 decimal places.)
(a) 1formula63.mml = 22, s = 3, n = 6, 90 percent confidence.
The 90% confidence interval is to (b) 1formula63.mml = 40, s = 4, n = 19, 99 percent confidence. The 99% confidence interval is to (c) 1formula63.mml = 123, s = 10, n = 20, 95 percent confidence. The 95% confidence interval is to
a)
90% confidence interval is 19.53 to 24.47
b)
99% confidence interval is 37.36 to 42.64
c)
95% confidence interval is 118.32 to 127.68
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