Question

How many 4-digit numbers can be formed from the digits 2, 3, 8 and 9?

Answer #1

There are 4 digits.

Case I) If the repitition of the digits are not allowed then,

For the 1st place there are four options, for the 2nd place there are three options, for the 3rd place there are 2 options and for the 4th place there are 1 option. So, the number of 4-digit numbers

= 4 × 3 × 2 × 1 = **24**

Therefore, the number of 4-digit numbers =
**24**

Case II) If the repitition of the digits are allowed then,

All places there are four options, So, the number of 4-digit
numbers = 4 × 4 × 4 × 4 = **256**

Therefore, the number of 4-digit numbers =
**256**

How many four-digit numbers can be formed from the digits 1,
3, 5, 7, 8, and 9 if the numbers are less than 3,000 and digits are
not used repeatedly? ( Hint: Begin with the digit where there is a
restriction on the choices.)

how
many four digit numbers can be formed from digits 1, 3, 5, 7 ,8 and
9.; if the numbers are less than 3000 th digits are not used
repeadetly.

(a) How many three-digit numbers can be formed from the digits
0 comma 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8
comma and 9
if each digit can be used only once?
(b) How many of these are odd numbers?
(c) How many are greater than 440?

How many possible 5 digit numbers can be formed with the 10
digits 0 to 9 if repetitions are not allowed and zero cannot be the
first digit?

Six-digit numbers are to be formed using only the digits in the
set:
A = {1, 2, 3, 4, 5, 6, 7, 8}
How many such numbers can be formed if repetitions of the
digits are allowed?
In part (a), how many of the numbers contain at least one 3 and
at least one 5?
c. How many 6-digit numbers can be formed if each digit in A can
be used at most once?

how
many odd numbers can be formed from the digits 0,1,2,3,4,5,6 if
each digit can be used only once?

(a) How many numbers can be formed by arranging the digits 1, 2,
2, 4, 6, 6, 6?
(b) How many numbers greater than 3,000,000 can be formed by
arranging the digits 1, 2, 2, 4, 6, 6, 6?

How many two-digit counting numbers do not contain any of the
digits 1, 3, or 9?
42 numbers
72 numbers
81 numbers
49 numbers

10. Three-digit numbers are to be made from the 10 digits 0, 1,
2, …, 9. (Assume that the first digit cannot be 0.)
a. How many numbers can be made if repetitions are not allowed
and the number must be divisible by 10?
b. How many numbers can be made if repetitions are allowed and
the number must be even?
c. How many numbers can be made if repetitions are not allowed
and the number must be odd and...

How many diffrent two-digit numbers can you use the
digits 4,3,7,1,2,6, and 9 without repetition? For example, 77 is
not allowed
The number of diffrent two-digit number is

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