Question

A random sample of 1200 car owners in a particular city found 384 car owners who...

A random sample of 1200 car owners in a particular city found 384 car owners who received a speeding ticket this year. Find a 95% confidence interval for the true percent of car owners in this city who received a speeding ticket this year. Express your results to the nearest hundredth of a percent.

Answer: ___________to ___________%

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Given that, n = 1200 and x = 384

=> sample proportion = 384/1200 = 0.32

A 95% confidence level has significance level of 0.05 and critical value is,

The 95% confidence interval for the population proportion is,

Answer : 29.36 to 34.64 %

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of 1800 car owners in a particular city found 324 car owners who...
A random sample of 1800 car owners in a particular city found 324 car owners who received a speeding ticket this year. Find a 95% confidence interval for the true percent of car owners in this city who received a speeding ticket this year. Express your results to the nearest hundredth of a percent. Answer: to  %
HW 25 A random sample of 1300 home owners in a particular city found 143 home...
HW 25 A random sample of 1300 home owners in a particular city found 143 home owners who had a swimming pool in their backyard. Find a 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard. Express your results to the nearest hundredth of a percent. . Answer: ___ to ___ %
A random sample of 1900 workers in a particular city found 494 workers who had full...
A random sample of 1900 workers in a particular city found 494 workers who had full health insurance coverage. Find a 95% confidence interval for the true percent of workers in this city who have full health insurance coverage. Express your results to the nearest hundredth of a percent. Answer: _______   to________ %
A random sample of 1300 voters in a particular city found 273 voters who voted yes...
A random sample of 1300 voters in a particular city found 273 voters who voted yes on proposition 200. Find a 95% confidence interval for the true percent of voters in this city who voted yes on proposition 200. Express your results to the nearest hundredth of a percent.
A random sample of 2000 voters in a particular city found 820 voters who voted yes...
A random sample of 2000 voters in a particular city found 820 voters who voted yes on proposition 200. Find a 95% confidence interval for the true percent of voters in this city who voted yes on proposition 200. Express your results to the nearest hundredth of a percent.
A random sample of 700 voters in a particular city found 266 voters who voted yes...
A random sample of 700 voters in a particular city found 266 voters who voted yes on proposition 200. Find a 95% confidence interval for the true percent of voters in this city who voted yes on proposition 200. Express your results to the nearest hundredth of a percent.
(1 point) A random sample of 800 workers in a particular city found 296 workers who...
(1 point) A random sample of 800 workers in a particular city found 296 workers who had full health insurance coverage. Find a 95% confidence interval for the true percent of workers in this city who have full health insurance coverage. Express your results to the nearest hundredth of a percent. . Answer: _______to_________ %
Please show work so I can understand how to solve thanks A random sample of 800...
Please show work so I can understand how to solve thanks A random sample of 800 adults in Flagstaff found 24 adults who had lost a job in the past year. Find a 95% confidence interval for the true percent of adults in Flagstaff who have lost a job in the past year. Express your results to the nearest hundredth of a percent. . Answer: to    %
A random sample of 1200 Freshmen at UGA were asked if they had applied for student...
A random sample of 1200 Freshmen at UGA were asked if they had applied for student football tickets. The proportion who answered yes was 0.86. The standard error of this estimate is 0.010. (a) Find the margin of error for a 95% confidence interval for the population proportion who applied for football tickets. (3 decimal places) (b) Construct the 95% confidence interval. Lower Limit (3 decimal places) Upper Limit (3 decimal places) (c) Since the sample was randomly selected, will...
A random sample of 56 credit card holders showed that 41 regularly paid their credit card...
A random sample of 56 credit card holders showed that 41 regularly paid their credit card bills on time. 1 Let P represent the proportion of all people who regularly paid their credit card bills on time.    Find a point estimate P for P ( use decimal form and round to the nearest hundredth). a. What is the critical value Z used to find a 95% confidence interval? b.   What is the margin of error EBP? (round to the nearest...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT