Based on historical data, your manager believes that 27% of the
company's orders come from first-time customers. A random sample of
152 orders will be used to estimate the proportion of
first-time-customers. What is the probability that the sample
proportion is less than 0.33?
Solution :
Given that ,
p = 0.27
1 - p = 0.73
n = 152
= p = 0.27
= (p*(1-p))/n = (0.27*0.73)/ 152= 0.0360
P( < 0.33) = P(( - ) / < (0.33 - 0.27) / 0.0360)
= P(z < 1.67)
= 0.9525
Probability = 0.9525
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