For women aged 18-24, systolic blood pressures (in mm Hg) are normally distributed with a mean of 114.8 and a standard deviation of 13.1. If 23 women aged 18-24 are randomly selected, find the probability that their mean systolic blood pressure is between 119 and 122.
Solution :
Given that,
mean = = 114.8
standard deviation = = 13.1
= / n = 13.1 / 23 = 2.7315
= P[(119 - 114.8) /2.7315 < ( - ) / < (122 - 114.8) / 2.7315)]
= P(1.54 < Z < 2.64)
= P(Z < 2.64) - P(Z < 1.54)
= 0.9959 - 0.9382
= 0.0577
Probability = 0.0577
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