1) Adult Golden Retrievers have a mean weight of 64 pounds with a standard deviation of 8 pounds. If you take a random sample of 50 adult Golden Retrievers, what would be the standard deviation of the sample distribution, σ¯¯¯XσX¯?
2) Adult Golden Retrievers have a mean weight of 64 pounds with a standard deviation of 8 pounds. If you take a random sample of 35 gold retrievers, what is the probability the sample mean will be less than 65.5 pounds?
3) A random sample of 200 adults is taken from a population of 20000. It is believed that 86% of adults own a cell phone. Find the probability the sample proportion is between 84% and 87%
Solution:-
1) The standard deviation of the sample distribution is 1.1314.
2) The probability the sample mean will be less than 65.5 pounds is 0.134.
n = 35, Mean = 64, S.D = 8
x = 65.5
By applying normal distribution:-
z = 1.109
Use the z-score table or p-value calculator.
P(z > 1.109) = 0.134
3) The probability the sample proportion is between 84% and 87% is 0.4530.
p = 0.86, n = 200
p1 = 0.84
p2 = 0.87
By applying normal distribution:-
z1 = - 0.815
z2 = 0.4075
P( - 0.815 < z < 0.4075) = P(z > - 0.815) - P(z > 0.4075)
P( - 0.815 < z < 0.4075) = 0.7925 - 0.3418
P( - 0.815 < z < 0.4075) = 0.4507
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