Solution :
This is the left tailed test .
The null and alternative hypothesis is
H0 : p = 0.50
Ha : p < 0.50
n = 100
= 0.39
P0 = 0.50
1 - P0 = 1 - 0.50 = 0.50
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
=0.39- 0.50 / [(0.50*0.50) / 100 ]
= -2.2
Test statistic = z = -2.2
P(z < -2.2 ) = 0.0139
P-value = 0.0139
= 0.01
P-value >
0.0139 > 0.01
Fail to reject the null hypothesis .
There is not sufficient evidence to suggest that
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