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It is known that 12% of children are nearsighted. A random sample of 170 children is...

It is known that 12% of children are nearsighted. A random sample of 170 children is selected. What is the probability of less than 14% of this sample will be nearsighted?

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Answer #1

Solution

Given that,

p = 0.12

1 - p = 1 - 0.12 = 0.88

n = 170

= p = 0.12

=  [p ( 1 - p ) / n] =   [(0.12 * 0.88) / 170 ] = 0.0249

P( < 0.14)

= P[( - ) / < (0.14 - 0.12) / 0.0249 ]

= P(z < 0.80)

Using z table,

= 0.7881

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