Identify the symmetrical interval that includes 95% of the sample means for a population with a mean equal to 51 and a standard deviation equal to 12 using a sample size of 36. What is the lower bound and upper bound of this interval?
Solution :
Given that,
Z/2 = Z0.025 = 1.96
Margin of error = E = Z/2
* (
/n)
= 1.96 * ( 12 / 36
)
= 3.92
At 95% confidence interval estimate of the population mean is,
± E
51 ± 3.92
= ( 47.08, 54.92 )
Lower bound = 47.08
Upper bound = 54.92
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