Question

I did a two sample t-test to compare heart rate in men and women during long runs

the null hypothesis is women have higher rates while running in comparison to males

heart rate 1

N₁: 10
df₁ = N - 1 = 10 - 1 = 9
M₁: 174.2
SS₁: 5241.6
s²₁ = SS₁/(N - 1) = 5241.6/(10-1) = 582.4

heart rate 2

N₂: 10
df₂ = N - 1 = 10 - 1 = 9
M₂: 176.8
SS₂: 4199.6
s²₂ = SS₂/(N - 1) = 4199.6/(10-1) = 466.62


T-value Calculation

s²_p = ((df₁/(df₁ + df₂)) * s²₁) + ((df₂/(df₂ + df₂)) * s²₂) = ((9/18) * 582.4) + ((9/18) * 466.62) = 524.51

s²_M1 = s²_p/N₁ = 524.51/10 = 52.45
s²_M2 = s²_p/N₂ = 524.51/10 = 52.45

t = (M₁ - M₂)/√(s²_M1 + s²_M2) = -2.6/√104.9 = -0.25

Significance Level: .05

the test is one-tailed and looking at critical t. at df =18, I cant tell if it's significant enough to reject the null. T-table at df 18= (-)1.73, is it significant & why? Can I reject the null?

Answer 1

FROM NORMAL CURVE T = - 0.25 DOESNOT FALL IN REJECTION REGION SO DO NOT REJECT H

IS IT SIGNIFICANT : NO

CAN I REJECT THE NULL : NO