Question

A simple random sample from a population with a normal distribution of 9999 body temperatures has x bar =98.40 F degrees

and s =0.68 F° . Construct an 80% confidence interval estimate of the standard deviation of body temperature of all healthy humans.

( Can you tell me exactly how can find X_{L}^{2
}X_{R}^{2.} )

Answer #1

A simple random sample from a population with a normal
distribution of 99 body temperatures has x overbarxequals=99.10
degrees °F and s=0.65 degrees F°. Construct an 80% confidence
interval estimate of the standard deviation of body temperature of
all healthy humans.

A simple random sample from a population with a normal
distribution of 106 body temperatures has x=98.50degrees Upper F
and s=0.63degrees Upper F. Construct a 98% confidence interval
estimate of the standard deviation of body temperature of all
healthy humans. A simple random sample from a population with a
normal distribution of 106 body temperatures has x = 98.50degrees
Upper F and s=0.63degrees Upper F. Construct a 98% confidence
interval estimate of the standard deviation of body temperature of
all...

A simple random sample from a population with a normal
distribution of 109 body temperatures has x
overbarequals98.30degrees Upper F and sequals0.67degrees Upper F.
Construct an 80% confidence interval estimate of the standard
deviation of body temperature of all healthy humans.

A simple random sample from a population with a normal
distribution of 100 body temperatures has x=98.90 degrees Upper F°F
and s=0.63 degrees Upper F°F. Construct an 95% confidence interval
estimate of the standard deviation of body temperature of all
healthy humans.

A simple random sample from a population with a normal
distribution of 108 body temperatures has
x overbar x equals=98.8 degrees F° and sequals=0.63 degrees
F°.
Construct a 95%confidence interval estimate of the standard
deviation of body temperature of all healthy humans.

A simple random sample from a population with a normal
distribution of
107107
body temperatures has
x overbarxequals=98.3098.30degrees Upper F°F
and
sequals=0.680.68degrees Upper F°F.
Construct
aa
9999%
confidence interval estimate of the standard deviation of body
temperature of all healthy humans.
LOADING...
Click the icon to view the table of Chi-Square critical
values.

A simple random sample from a population with a normal
distribution of 105 body temperatures has x =98.1°F and s=0.61°F.
Construct a 90%
confidence interval estimate of the standard deviation of body
temperature of all healthy humans.

A simple random sample from a population with a normal
distribution of 104 body temperatures has x=98.50degrees F and
s=0.69degrees F. Construct a 90% confidence interval estimate of
the standard deviation of body temperature of all healthy
humans
____F<o<____ F

A simple random sample from a population with a normal
distribution of 99 body temperatures has x
overbarequals98.90degrees Upper F and sequals0.62degrees Upper F.
Construct a 95% confidence interval estimate of the standard
deviation of body temperature of all healthy humans. LOADING...
Click the icon to view the table of Chi-Square critical
values.

A simple random sample from a population with a normal
distribution of 100 body temperatures has
x overbar =9 8.40°F ands = 0.62°F.
Construct a 98% confidence interval estimate of the standard
deviation of body temperature of all healthy humans. Is it safe to
conclude that the population standard deviation is less than
2.10°F?
___°F < σ < ___°F
(Round to two decimal places as needed.)
Is it safe to conclude that the population standard deviation is
less than 2.10°F?...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 3 minutes ago

asked 15 minutes ago

asked 15 minutes ago

asked 18 minutes ago

asked 49 minutes ago

asked 57 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago