The population proportion is 0.40. What is the probability that a sample proportion will be within ±0.04 of the population proportion for each of the following sample sizes? (Round your answers to 4 decimal places.) (a) n = 100
Solution :
Given that ,
p = 0.40
1 - p = 0.60
a)
n = 100
= p = 0.40
= (p*(1-p))/n = (0.40*0.60)/ 100= 0.04899
P(0.36 < <0.44 ) = P((0.36-0.40)/0.04899 ) < ( - ) / < (0.44-0.40) /0.04899 ) )
= P(-0.82 < z < 0.82)
= P(z < 0.82) - P(z < -0.82)
= 0.7939 - 0.2061
= 0.5878
Probability = 0.5878
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