Question

Please don't copy and paste the answer from another person's question that was already asked. I...

Please don't copy and paste the answer from another person's question that was already asked. I already saw those and I wouldn't be posting this if I wanted to see those answers. Thank you!

SHOW WORK!!!!! Full credit will not be given for answers only. NOTE: for any question asking you to determine a probability----you MUST write out a probability statement using proper notation!!!! Probabilities should be DECIMAL form and rounded to 4 decimal places.

Jack is a collegiate high jumper. The heights of his jumps follow a normal distribution with an average of 6 feet 3 inches with a standard deviation of 8 inches. Let Y be the height of one of Jack’s jump. (Note: high jumpers try to jump over a bar that is set at a particular height for an attempt. Clearing the bar means that the high jumper went over the bar w/o knocking it down.)

a) The bar is currently set at 7 feet 3 inches. What is the probability that Jack does not clear the bar?
b) What is the probability that Jack jumps at least 8 feet in his attempt?
c) What is the probability that Jack’s attempt is within 5 inches of his average?
d) What is the 90th percentile of Jack’s jump heights?
e) Jack has already done a few jumps in a competition and is very tired. He knows that on his next jump he can only jump at most 7 feet. If the bar is set at 6.17 feet, what is the probability that he clears it?

Homework Answers

Answer #1

Y is the random variable denoting the height jumped by Jack in inches .

Note that 6 feet 3 inches = 75 inches

So, Y~N( 75 , 8)

a) P[ Jack does not clear the bar]

b) P[ Jack attempts at least 8 ft]

c) Jacks average is 75 inches .

So we need to find :

d) Let p be the 90th percentile ,

Then by definition of percentile :

inches or 7.105 ft.

e) 6.17 ft = 6.17 x 12 inches = 74.04 inches .

We need to find :

* where Z~N(0,1)

  

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