The home run percentage is the number of home runs per 100 times at bat. A random sample of 43 professional baseball players gave the following data for home run percentages.
1.6 | 2.4 | 1.2 | 6.6 | 2.3 | 0.0 | 1.8 | 2.5 | 6.5 | 1.8 |
2.7 | 2.0 | 1.9 | 1.3 | 2.7 | 1.7 | 1.3 | 2.1 | 2.8 | 1.4 |
3.8 | 2.1 | 3.4 | 1.3 | 1.5 | 2.9 | 2.6 | 0.0 | 4.1 | 2.9 |
1.9 | 2.4 | 0.0 | 1.8 | 3.1 | 3.8 | 3.2 | 1.6 | 4.2 | 0.0 |
1.2 | 1.8 | 2.4 |
(a) Use a calculator with mean and standard deviation keys to find x and s. (Round your answers to two decimal places.)
x = | |
s = |
(b) Compute a 90% confidence interval for the population mean μ
of home run percentages for all professional baseball players.
Hint: If you use the Student's t distribution
table, be sure to use the closest d.f. that is
smaller. (Round your answers to two decimal places.
lower limit
upper limit
(c) Compute a 99% confidence interval for the population mean μ of home run percentages for all professional baseball players. (Round your answers to two decimal places.)
lower limit
upper limit
(a) From the given data
= 2.29
s = 1.40
_____________
(b) 90% CI
t critical for df = n - 1 = 42 for = 0.1 is 1.68
The Lower Limit = - tcritical * s / sqrt(n) = 2.29 - 1.68 * 1.4 / sqrt(43) = 1.93
The Upper Limit = + tcritical * s / sqrt(n) = 2.29 + 1.68 * 1.4 / sqrt(43) = 2.65
The 90% CI is (1.93, 2.65)
____________
(b) 99% CI
t critical for df = n - 1 = 42 for = 0.01 is 2.698
The Lower Limit = - tcritical * s / sqrt(n) = 2.29 - 2.698 * 1.4 / sqrt(43) = 1.71
The Upper Limit = + tcritical * s / sqrt(n) = 2.29 + 2.698 * 1.4 / sqrt(43) = 2.87
The 99% CI is (1.71, 2.87)
____________
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