The accompanying table lists the numbers of words spoken in a day by each member of
56
different randomly selected couples. Complete parts (a) and (b) below
Male Female
28,318 19,830
17,170 23,071
3,896 4,269
29,439 18,574
24,265 12,044
8,740 14,884
19,875 11,237
16,529 19,452
26,558 13,036
21,742 19,734
10,094 16,432
12,281 13,765
10,927 17,777
19,776 23,963
18,776 5,567
2,082 16,597
21,459 22,032
10,191 18,234
18,738 14,988
15,314 13,702
14,995 28,030
19,158 8,367
7,914 18,943
6,664 5,057
27,001 10,509
9,688 18,386
15,390 13,872
10,622 20,049
13,030 21,233
19,201 10,978
15,115 35,478
9,674 7,658
19,043 12,493
16,434 12,009
10,575 31,573
13,180 21,329
13,954 18,208
11,507 18,798
17,784 21,930
12,311 15,108
12,233 20,054
6,682 13,927
19,005 17,720
14,573 14,614
17,019 30,798
14,648 37,737
19,598 26,085
38,253 33,865
18,184 23,480
47,564 29,711
24,907 18,903
11,216 7,219
15,087 24,810
9,229 14,862
6,288 13,057
20,368 26,728
a. Use a
0.050.05
significance level to test the claim that among couples, males speak fewer words in a day than females.In this example,
mu Subscript dμd
is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis test?
Upper H 0H0:
mu Subscript dμd
▼
greater than>
equals=
not equals≠
less than<
nothing word(s)
Upper H 1H1:
mu Subscript dμd
▼
less than<
equals=
greater than>
not equals≠
nothing word(s)
(Type integers or decimals. Do not round.)
Identify the test statistic.
tequals=nothing
(Round to two decimal places as needed.)
Identify the P-value.
P-valueequals=nothing
(Round to three decimal places as needed.)
What is the conclusion based on the hypothesis test?
Since the P-value is
▼
greater than
less than or equal to
the significance level,
▼
reject
fail to reject
the null hypothesis. There
▼
is not
is
sufficient evidence to support the claim that males speak fewer words in a day than females.
b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)?
The confidence interval is
nothing
word(s)less than<mu Subscript dμdless than<nothing
word(s).
(Round to one decimal place as needed.)
What feature of the confidence interval leads to the same conclusion reached in part (a)?
Since the confidence interval contains
▼
only positive numbers,
zero,
only negative numbers,
▼
fail to reject
reject
the null hypothesis.
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