At a local college, 297 of the male students are smokers and are 693 non-smokers. Of the female students 180, are smokers and 720 are non-smokers. A male student and a female student from the college are randomly selected for a survey. What is the probability that both are non-smokers? Do not round your answer.
P(selecting a non-smoker male out of all the males) = (No. of non-smoker males)/(Total no. of males)
= 693/(297+693)
= 693/990
= 0.7
P(selecting a non-smoker female out of all the females) = (No. of non-smoker females)/(Total no. of females)
= 720/(180+720)
= 720/900
= 0.8
Thus, if a male and a female student are selected, then the probability that both are non-smokers = P(selecting a non-smoker male out of all the males)*P(selecting a non-smoker female out of all the females)
= 0.7*0.8
= 0.56 [Answer]
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