Question
Trials Results Column1 Column2 Column3 Column4 Column5 Column6 1.F 11. S 21. S 31. F 41....
| Trials Results | Column1 | Column2 | Column3 | Column4 | Column5 | Column6 |
| 1.F | 11. S | 21. S | 31. F | 41. S | 51. F | 61. S |
| 2.F | 12. F | 22. F | 32. S | 42. F | 52. F | 62. S |
| 3.S | 13. F | 23. F | 33. S | 43. F | 53.F | 63. S |
| 4.F | 14. F | 24. S | 34. S | 44. F | 54. F | 64. F |
| 5.S | 15. F | 25. F | 35. F | 45. F | 55. F | 65. F |
| 6.S | 16. S | 26. F | 36. F | 46. S | 56. F | 66. F |
| 7.S | 17. S | 27. S | 37.F | 47. S | 57. F | 67. F |
| 8.F | 18. S | 28. S | 38. F | 48. S | 58. S | 68. F |
| 9.S | 19. S | 29. F | 39. S | 49. F | 59. S | 69. F |
| 10. S | 20. S | 30. S | 40. S | 50. F | 60. F | 70. S |
The number of successes is 32 and failures is 38.
1) What is the probability that you’d get exactly 35 successes in your 70 trials?
2) Find the mean number of successes you’d expect to get in your 70 trials.
Homework Answers
Answer #1
Given :- number of success =32
Number of failure = 38
Answer:- n= 32+38=40
Therefore ,probability of success (p)= 32/70 =0.457
Probability of failure(q)= 38/70 = 0.543
Here we use binomial distribution because number of trial is finite and probability of success is constant for each trial .
Let's X be the no. Of success.
A) P(X=35) = (70C35)((0.457)^35)((0.543)^35)
P(X=35) = 0.0733
Probability that exactly 35 success is 0.0733
B) mean = np
=70 × 0.457 = 31.99
OR,
BY NORMAL DISTRIBUTION as an approximation to the BINOMIAL DISTRIBUTION
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