Question

1(b). A Basketball player shoot three free throws, random variables X and respective probabilities P(X) are given in Table . Find the Standard Deviation of the discrete random variable from given Table.

X	P(X)
0	0.03
1	0.08
2	0.40
3	0.49

Answer 1

Solution :

Mean = = X * P(X)

= 0 *03 + 1 * 0.08 + 2 *0.40 + 3 * 0.49

= ( 0+0.08 + 0.8 +1.47 )

= 2.35

Standard deviation =

=X 2 * P(X) - 2

=  [ 02 *03 + 12 * 0.08 + 22 *0.40 + 32 * 0.49]-2.352

= [( 0+ 0.08+ 1.6+ 4.41) )] -5.5225

= 6.09-5.5225

=0.5675

Standard deviation = =0.7533