Question

In a study of the accuracy of fast food​ drive-through orders, Restaurant A had 304 accurate...

In a study of the accuracy of fast food​ drive-through orders, Restaurant A had 304 accurate orders and

72 that were not accurate. a. Construct a 90​% confidence interval estimate of the percentage of orders that are not accurate. b. Compare the results from part​ (a) to this

90​% confidence interval for the percentage of orders that are not accurate at Restaurant​ B: 0.1730.173less than<pless than<0.2470.247. What do you​ conclude?

Express the percentages in decimal form.

Homework Answers

Answer #1

Solution:-

a) 90​% confidence interval estimate of the percentage of orders that are not accurate is (0.1581,0.2249).

x = 72, n = 304

b)

90​% confidence interval estimate of the percentage of orders that are not accurate for restaurant A = (0.158,0.225)

90​% confidence interval estimate of the percentage of orders that are not accurate for restaurant B = (0.173, 0.247)

Both the intervals contains common values, hence we can conclude that there is no difference in the  percentage of orders that are not accurate for restaurants A and restaurant B.

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