The times per week a student uses a lab computer are normally distributed, with a mean of 6.3 hours and a standard deviation of 1.2 hours. A student is randomly selected. Find the following probabilities.
(a) Find the probability that the student uses a lab computer less than 5 hours per week.
(b) Find the probability that the student uses a lab computer between 6 and 8 hours per week.
(c) Find the probability that the student uses a lab computer more than 9 hours per week.
Solution :
(a)
P(x < 5) = P[(x - ) / < (5 - 6.3) / 1.2]
= P(z < -1.08)
= 0.1401
probability = 0.1401
(b)
P(6 < x < 8) = P[(6 - 6.3)/ 1.2) < (x - ) / < (8 - 6.3) / 1.2) ]
= P(-0.25 < z < 1.42)
= P(z < 1.42) - P(z < -0.25)
= 0.9222 - 0.4013
= 0.5209
Probability = 0.5209
(c)
P(x > 9) = 1 - P(x < 9)
= 1 - P[(x - ) / < (9 - 6.3) / 1.2)
= 1 - P(z < 2.25)
= 1 - 0.9878
= 0.0122
Probability = 0.0122
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