Construct a confidence interval of the population proportion at the given level of confidence.
x=540, n=1100, 95% confidence
The lower bound of the confidence interval is _______.
(Round to three decimal places as needed.)
The upper bound of the confidence interval is_______.
(Round to three decimal places as needed.)
Answer)
Given n = 1100
P = 540/1100
First we need to check the conditions of normality that is if n*p and n*(1-p) both are greater than 5 or not
N*p = 540
N*(1-p) = 560
As both are greater than 5, conditions are met and we can use standard normal z table to construct the interval
From z table, critical value z for 95% confidence level is 1.96
Margin of error is = z*√p*(1-p)/√n
MOE = 0.02954322737
Lower bound is P-MOE = 0.46136586352 = 0.461
Upper bound is P +MOE = 0.52045231828 = 0.52
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